**What is non terminating repeating decimal ? **

*Naomi Sbicca BlackBrown Naomi BlackBrown Sbicca Sbicca Naomi* A decimal number that continues infinitely with repeated pattern. *BlackBrown Sbicca BlackBrown Naomi Sbicca Naomi Naomi Sbicca*

**Examples : **

**23.562562562..........................(Repeated pattern is 562)**

**1.3333333333..........................(Repeated pattern is 3)**

**2.365636563656......................(Repeated pattern is 3656)**

In the above three examples, digits after the decimal point continue infinitely with a repeated pattern.

How do we have this non terminating repeating decimal in math ?

When we divide an integer by another integer, we may get the result in different forms.

In those results, non terminating repeating decimal is one of the forms.

Let us consider the fraction 125 / 99.

When we divide 125 by 99, we get "Non terminating repeating decimal".

It has been explained below.

From the above long division, we can clearly understand how we have non terminating repeating decimal.

Therefore, **125 / 99 = 1.262626..........................**

When we divide 125 by 99, the digits after the decimal keep going infinitely and the repeated pattern is 26.

**Step 1 : **

**Let x = Given decimal number **

**For example, **

**If the given decimal number is 2.0343434......... **WhiteCement PeachWhite Blue Vintage Blue Saucony TanGrey WhiteTeal Jazz Blue Originals Original Rq7OF

**then, let x = 2.0343434...........**

**Step 2 : **

**Identify the repeated pattern**

**For example,**

**In 2.0343434..........., the repeated pattern is 34**

**(Because 34 is being repeated)**

**Step 3 :**

**Identify the first repeated pattern and second repeated pattern as as explained in the example given below. **

**BlackBrown Sbicca Sbicca Naomi Naomi Naomi BlackBrown Sbicca Step 4 :**

**Count the number of digits between the decimal point and first repeated pattern as given in the picture below. **

**Step 5 :**

**Since there is 1 digit between the decimal point and the first repeated pattern, we have to multiply the given decimal by 10 as given in the picture below. **

**(If there are two digits -----------> multiply by 100, **

**three digits -----------> multiply by 1000 and so on )**

**Note : In (1), we have only repeated patterns after the decimal.**

**Step 6 : **

**Count the number of digits between the decimal point and second repeated pattern as given in the picture below.**

**Step 7 :**

**Since there are 3 digits between the decimal point and the second repeated pattern, we have to multiply the given decimal by 1000 as given in the picture below. **

**Note : In (2), we have only repeated patterns after the decimal.**

**Step 8 :**

**Now, we have to subtract the result of step 5 from step 7 as given in the picture below. **

**Now we got the fraction which is equal to the given decimal**

Naomi Naomi Sbicca Naomi Sbicca BlackBrown BlackBrown Sbicca To have better understanding on conversion of non terminating repeating decimals to fraction, let us look at some problems.

**Problem 1 :**

Covert the given non terminating repeating decimal into fraction

**32.03256256256..........**

**Solution : **

Let X = 32.03256256256.............

Here, the repeated pattern is 256

No. of digits between the 1st repeated pattern and decimal = 2

So, multiply the given decimal by 100. Then, we have

**100X = 3203.256256256...............----------(1) **

No. of digits between the 2nd repeated pattern and decimal = 5

So, multiply the given decimal by 100000. Then, we have

**100000X = 3203256.256256256...............----------(2)**

(2) - (1) --------> 99900X = 3200053

X = 3200053 / 99900

**Hence, 32.03256256256.......... = 3200053 / 99900**

**Problem 2 :**

Covert the given non terminating repeating decimal into fraction

**0.01232222........**

**Solution : **

Let X = 0.01232222.............

Here, the repeated pattern is 2

No. of digits between the 1st repeated pattern and decimal = 4

(Here, the first repeated pattern starts after four digits of the decimal)

So, multiply the given decimal by 10000. Then, we have

**10000X = 123.2222...............----------(1) **WhiteCherry Grey Supra Champagne White Anevay Black WhiteCork Champagne Gold BoneWhite BoneDark E1YxgYqFwn

No. of digits between the 2nd repeated pattern and decimal = 5

So, multiply the given decimal by 100000. Then, we have

**100000X = 1232.2222...............----------(2)**

(2) - (1) --------> 90000X = 1109

X = 1109 / 90000

**Hence, 0.01232222........... = 1109 / 90000**

**Problem 3 :**

Covert the given non terminating repeating decimal into fraction

**2.03323232..........**

**Solution : **

Let X = 2.03323232.............

Here, the repeated pattern is 32

No. of digits between the 1st repeated pattern and decimal = 2

(Here, the first repeated pattern starts after two digits of the decimal)

So, multiply the given decimal by 100. Then, we have

**100X = 203.323232...............----------(1) **

No. of digits between the 2nd repeated pattern and decimal = 4

So, multiply the given decimal by 10000. Then, we have

**10000X = 20332.323232...............----------(2)**

(2) - (1) --------> 9900X = 20129

X = 9900 / 20129

**Hence, 2.03323232.......... = 9900 / 20129**

**Problem 4 :**

BlackBrown Naomi Sbicca Naomi Sbicca Naomi BlackBrown Sbicca Covert the given *Naomi Sbicca Sbicca Sbicca BlackBrown Naomi BlackBrown Naomi* non terminating repeating decimal into fraction

**0.252525..........**

**Solution : **

Let X = 0.252525.............

Here, the repeated pattern is 25

No. of digits between the 1st repeated pattern and decimal = 0

So, multiply the given decimal by 1. Then, we have

**X = 0.252525...............----------(1) **LeatherSaddle Campus Leather LeatherBlazer LeatherDark LeatherBlack Banana Brown Brown 14L Frye BPFxn88

No. of digits between the 2nd repeated pattern and decimal = 2

So, multiply the given decimal by 100. Then, we have

**100X = 25.252525...............----------(2)**

*Sbicca Sbicca Naomi Naomi BlackBrown Sbicca Naomi BlackBrown* (2) - (1) --------> 99X = 25

X = 25 / 99

**Hence, 0.252525.......... = 25 / 99**

**Problem 5 :**

Covert the given non-terminating repeating decimal into fraction

**3.3333..........**

**Solution : **

Let X = 3.3333.............

Here, the repeated pattern is 3

No. of digits between the 1st repeated pattern and decimal = 0

(Here, the first repeated pattern is "3" which comes right after the decimal point)

So, multiply the given decimal by 1. Then, we have

**X = 3.3333...............----------(1) **

No. of digits between the 2nd repeated pattern and decimal = 1

(Here, the second repeated pattern is "3" which comes one digit after the decimal point)

So, multiply the given decimal by 10. Then, we have

**10X = 33.3333...............----------(2)**

(2) - (1) --------> 9X = 30

X = 30 / 9 = 10 / 3

**Hence, 3.3333.............. = 10 / 9**

**Problem 6 :**

Covert the given non-terminating repeating decimal into fraction

**1.023562562562..........**

**Solution : **

Let X = 1.023562562562.............

Here, the repeated pattern is 562

No. of digits between the 1st repeated pattern and decimal = 3

So, multiply the given decimal by 1000. Then, we have

**1000X = 1023.562562562...............----------(1) **

No. of digits between the 2nd repeated pattern and decimal = 6

So, multiply the given decimal by 1000000. Then, we have

**1000000X = 1023562.562562562...............----------(2)**

(2) - (1) --------> 999000X = 1022538

X = 1022539 / 999000

**Hence, 1.023562562562.......... = ****1022539 / 999000**

After having gone through the stuff and examples, we hope that the students would have understood, "non-terminating repeating decimal"

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**Converting decimals into fractions**

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