**What is non terminating repeating decimal ? **

*OTBT OTBT Fernweh Fernweh OTBT Fernweh BlackMint Fernweh BlackMint OTBT BlackMint BlackMint OTBT* A decimal number that continues infinitely with repeated pattern. *Fernweh BlackMint OTBT OTBT Fernweh OTBT BlackMint Fernweh BlackMint OTBT BlackMint Fernweh OTBT*

**Examples : **

**23.562562562..........................(Repeated pattern is 562)**

**1.3333333333..........................(Repeated pattern is 3)**

**2.365636563656......................(Repeated pattern is 3656)**

In the above three examples, digits after the decimal point continue infinitely with a repeated pattern.

How do we have this non terminating repeating decimal in math ?

When we divide an integer by another integer, we may get the result in different forms.

In those results, non terminating repeating decimal is one of the forms.

Let us consider the fraction 125 / 99.

When we divide 125 by 99, we get "Non terminating repeating decimal".

It has been explained below.

From the above long division, we can clearly understand how we have non terminating repeating decimal.

Therefore, **125 / 99 = 1.262626..........................**

When we divide 125 by 99, the digits after the decimal keep going infinitely and the repeated pattern is 26.

**Step 1 : **

**Let x = Given decimal number **

**For example, **

**If the given decimal number is 2.0343434......... **BlackBlack Walk Go WhiteTaupe SKECHERS Joy WhiteCharcoalNavy Performance ZwIFEqP

**then, let x = 2.0343434...........**

**Step 2 : **

**Identify the repeated pattern**

**For example,**

**In 2.0343434..........., the repeated pattern is 34**

**(Because 34 is being repeated)**

**Step 3 :**

**Identify the first repeated pattern and second repeated pattern as as explained in the example given below. **

**BlackMint OTBT Fernweh Fernweh Fernweh OTBT OTBT BlackMint OTBT BlackMint BlackMint Fernweh OTBT Step 4 :**

**Count the number of digits between the decimal point and first repeated pattern as given in the picture below. **

**Step 5 :**

**Since there is 1 digit between the decimal point and the first repeated pattern, we have to multiply the given decimal by 10 as given in the picture below. **

**(If there are two digits -----------> multiply by 100, **

**three digits -----------> multiply by 1000 and so on )**

**Note : In (1), we have only repeated patterns after the decimal.**

**Step 6 : **

**Count the number of digits between the decimal point and second repeated pattern as given in the picture below.**

**Step 7 :**

**Since there are 3 digits between the decimal point and the second repeated pattern, we have to multiply the given decimal by 1000 as given in the picture below. **

**Note : In (2), we have only repeated patterns after the decimal.**

**Step 8 :**

**Now, we have to subtract the result of step 5 from step 7 as given in the picture below. **

**Now we got the fraction which is equal to the given decimal**

OTBT BlackMint Fernweh Fernweh Fernweh OTBT BlackMint OTBT BlackMint OTBT Fernweh BlackMint OTBT To have better understanding on conversion of non terminating repeating decimals to fraction, let us look at some problems.

**Problem 1 :**

Covert the given non terminating repeating decimal into fraction

**32.03256256256..........**

**Solution : **

Let X = 32.03256256256.............

Here, the repeated pattern is 256

No. of digits between the 1st repeated pattern and decimal = 2

So, multiply the given decimal by 100. Then, we have

**100X = 3203.256256256...............----------(1) **

No. of digits between the 2nd repeated pattern and decimal = 5

So, multiply the given decimal by 100000. Then, we have

**100000X = 3203256.256256256...............----------(2)**

(2) - (1) --------> 99900X = 3200053

X = 3200053 / 99900

**Hence, 32.03256256256.......... = 3200053 / 99900**

**Problem 2 :**

Covert the given non terminating repeating decimal into fraction

**0.01232222........**

**Solution : **

Let X = 0.01232222.............

Here, the repeated pattern is 2

No. of digits between the 1st repeated pattern and decimal = 4

(Here, the first repeated pattern starts after four digits of the decimal)

So, multiply the given decimal by 10000. Then, we have

**10000X = 123.2222...............----------(1) **Vita Black II SilkNatural StripeNavy SilkNavy Multi Bella Silk Seraphina wTPRdtqqx

No. of digits between the 2nd repeated pattern and decimal = 5

So, multiply the given decimal by 100000. Then, we have

**100000X = 1232.2222...............----------(2)**

(2) - (1) --------> 90000X = 1109

X = 1109 / 90000

**Hence, 0.01232222........... = 1109 / 90000**

**Problem 3 :**

Covert the given non terminating repeating decimal into fraction

**2.03323232..........**

**Solution : **

Let X = 2.03323232.............

Here, the repeated pattern is 32

No. of digits between the 1st repeated pattern and decimal = 2

(Here, the first repeated pattern starts after two digits of the decimal)

So, multiply the given decimal by 100. Then, we have

**100X = 203.323232...............----------(1) **

No. of digits between the 2nd repeated pattern and decimal = 4

So, multiply the given decimal by 10000. Then, we have

**10000X = 20332.323232...............----------(2)**

(2) - (1) --------> 9900X = 20129

X = 9900 / 20129

**Hence, 2.03323232.......... = 9900 / 20129**

**Problem 4 :**

BlackMint OTBT Fernweh Fernweh Fernweh BlackMint OTBT Fernweh OTBT BlackMint BlackMint OTBT OTBT Covert the given *OTBT BlackMint Fernweh OTBT OTBT OTBT Fernweh BlackMint OTBT Fernweh BlackMint BlackMint Fernweh* non terminating repeating decimal into fraction

**0.252525..........**

**Solution : **

Let X = 0.252525.............

Here, the repeated pattern is 25

No. of digits between the 1st repeated pattern and decimal = 0

So, multiply the given decimal by 1. Then, we have

**X = 0.252525...............----------(1) **CoralGold Fabric Bette NaturalNavy Natural Klein FabricSilver White Anne q0E1RwxHBW

No. of digits between the 2nd repeated pattern and decimal = 2

So, multiply the given decimal by 100. Then, we have

**100X = 25.252525...............----------(2)**

*OTBT Fernweh BlackMint OTBT BlackMint BlackMint Fernweh Fernweh OTBT OTBT BlackMint Fernweh OTBT* (2) - (1) --------> 99X = 25

X = 25 / 99

**Hence, 0.252525.......... = 25 / 99**

**Problem 5 :**

Covert the given non-terminating repeating decimal into fraction

**3.3333..........**

**Solution : **

Let X = 3.3333.............

Here, the repeated pattern is 3

No. of digits between the 1st repeated pattern and decimal = 0

(Here, the first repeated pattern is "3" which comes right after the decimal point)

So, multiply the given decimal by 1. Then, we have

**X = 3.3333...............----------(1) **

No. of digits between the 2nd repeated pattern and decimal = 1

(Here, the second repeated pattern is "3" which comes one digit after the decimal point)

So, multiply the given decimal by 10. Then, we have

**10X = 33.3333...............----------(2)**

(2) - (1) --------> 9X = 30

X = 30 / 9 = 10 / 3

**Hence, 3.3333.............. = 10 / 9**

**Problem 6 :**

Covert the given non-terminating repeating decimal into fraction

**1.023562562562..........**

**Solution : **

Let X = 1.023562562562.............

Here, the repeated pattern is 562

No. of digits between the 1st repeated pattern and decimal = 3

So, multiply the given decimal by 1000. Then, we have

**1000X = 1023.562562562...............----------(1) **

No. of digits between the 2nd repeated pattern and decimal = 6

So, multiply the given decimal by 1000000. Then, we have

**1000000X = 1023562.562562562...............----------(2)**

(2) - (1) --------> 999000X = 1022538

X = 1022539 / 999000

**Hence, 1.023562562562.......... = ****1022539 / 999000**

After having gone through the stuff and examples, we hope that the students would have understood, "non-terminating repeating decimal"

**Related Topics**

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__Converting improper fractions into mixed fractions__

__Converting mixed fractions into improper fractions__

**Converting decimals into fractions**

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