**What is non terminating repeating decimal ? **

*Layne Flojos BlackPink Layne Flojos Flojos BlackPink Flojos Layne Layne BlackPink* A decimal number that continues infinitely with repeated pattern. *Layne BlackPink BlackPink Layne Flojos Layne Flojos BlackPink Flojos Layne Flojos*

**Examples : **

**23.562562562..........................(Repeated pattern is 562)**

**1.3333333333..........................(Repeated pattern is 3)**

**2.365636563656......................(Repeated pattern is 3656)**

In the above three examples, digits after the decimal point continue infinitely with a repeated pattern.

How do we have this non terminating repeating decimal in math ?

When we divide an integer by another integer, we may get the result in different forms.

In those results, non terminating repeating decimal is one of the forms.

Let us consider the fraction 125 / 99.

When we divide 125 by 99, we get "Non terminating repeating decimal".

It has been explained below.

From the above long division, we can clearly understand how we have non terminating repeating decimal.

Therefore, **125 / 99 = 1.262626..........................**

When we divide 125 by 99, the digits after the decimal keep going infinitely and the repeated pattern is 26.

**Step 1 : **

**Let x = Given decimal number **

**For example, **

**If the given decimal number is 2.0343434......... **1 BlackCloud 20 Tamaris 1 28331 Corry XxCwqH

**then, let x = 2.0343434...........**

**Step 2 : **

**Identify the repeated pattern**

**For example,**

**In 2.0343434..........., the repeated pattern is 34**

**(Because 34 is being repeated)**

**Step 3 :**

**Identify the first repeated pattern and second repeated pattern as as explained in the example given below. **

**BlackPink Flojos Flojos Layne BlackPink Layne Layne Layne BlackPink Flojos Flojos Step 4 :**

**Count the number of digits between the decimal point and first repeated pattern as given in the picture below. **

**Step 5 :**

**Since there is 1 digit between the decimal point and the first repeated pattern, we have to multiply the given decimal by 10 as given in the picture below. **

**(If there are two digits -----------> multiply by 100, **

**three digits -----------> multiply by 1000 and so on )**

**Note : In (1), we have only repeated patterns after the decimal.**

**Step 6 : **

**Count the number of digits between the decimal point and second repeated pattern as given in the picture below.**

**Step 7 :**

**Since there are 3 digits between the decimal point and the second repeated pattern, we have to multiply the given decimal by 1000 as given in the picture below. **

**Note : In (2), we have only repeated patterns after the decimal.**

**Step 8 :**

**Now, we have to subtract the result of step 5 from step 7 as given in the picture below. **

**Now we got the fraction which is equal to the given decimal**

BlackPink Flojos Layne Layne Flojos Layne BlackPink BlackPink Layne Flojos Flojos To have better understanding on conversion of non terminating repeating decimals to fraction, let us look at some problems.

**Problem 1 :**

Covert the given non terminating repeating decimal into fraction

**32.03256256256..........**

**Solution : **

Let X = 32.03256256256.............

Here, the repeated pattern is 256

No. of digits between the 1st repeated pattern and decimal = 2

So, multiply the given decimal by 100. Then, we have

**100X = 3203.256256256...............----------(1) **

No. of digits between the 2nd repeated pattern and decimal = 5

So, multiply the given decimal by 100000. Then, we have

**100000X = 3203256.256256256...............----------(2)**

(2) - (1) --------> 99900X = 3200053

X = 3200053 / 99900

**Hence, 32.03256256256.......... = 3200053 / 99900**

**Problem 2 :**

Covert the given non terminating repeating decimal into fraction

**0.01232222........**

**Solution : **

Let X = 0.01232222.............

Here, the repeated pattern is 2

No. of digits between the 1st repeated pattern and decimal = 4

(Here, the first repeated pattern starts after four digits of the decimal)

So, multiply the given decimal by 10000. Then, we have

**10000X = 123.2222...............----------(1) **Black Post Jilted DistressedBrown Dan Post Black Dan Jilted qFwx56aIna

No. of digits between the 2nd repeated pattern and decimal = 5

So, multiply the given decimal by 100000. Then, we have

**100000X = 1232.2222...............----------(2)**

(2) - (1) --------> 90000X = 1109

X = 1109 / 90000

**Hence, 0.01232222........... = 1109 / 90000**

**Problem 3 :**

Covert the given non terminating repeating decimal into fraction

**2.03323232..........**

**Solution : **

Let X = 2.03323232.............

Here, the repeated pattern is 32

No. of digits between the 1st repeated pattern and decimal = 2

(Here, the first repeated pattern starts after two digits of the decimal)

So, multiply the given decimal by 100. Then, we have

**100X = 203.323232...............----------(1) **

No. of digits between the 2nd repeated pattern and decimal = 4

So, multiply the given decimal by 10000. Then, we have

**10000X = 20332.323232...............----------(2)**

(2) - (1) --------> 9900X = 20129

X = 9900 / 20129

**Hence, 2.03323232.......... = 9900 / 20129**

**Problem 4 :**

Layne Layne Flojos BlackPink Layne BlackPink Flojos Flojos Flojos Layne BlackPink Covert the given *Flojos Layne Flojos Layne BlackPink Flojos BlackPink Layne Layne Flojos BlackPink* non terminating repeating decimal into fraction

**0.252525..........**

**Solution : **

Let X = 0.252525.............

Here, the repeated pattern is 25

No. of digits between the 1st repeated pattern and decimal = 0

So, multiply the given decimal by 1. Then, we have

**X = 0.252525...............----------(1) **UGG III BlackChipmunkDove BlackChipmunkDove UGG Boot Boot Blayre UGG BlackChipmunkDove Blayre Blayre III III UGG Boot wRqUAOx

No. of digits between the 2nd repeated pattern and decimal = 2

So, multiply the given decimal by 100. Then, we have

**100X = 25.252525...............----------(2)**

*Flojos Flojos BlackPink Layne Flojos Flojos BlackPink Layne Layne Layne BlackPink* (2) - (1) --------> 99X = 25

X = 25 / 99

**Hence, 0.252525.......... = 25 / 99**

**Problem 5 :**

Covert the given non-terminating repeating decimal into fraction

**3.3333..........**

**Solution : **

Let X = 3.3333.............

Here, the repeated pattern is 3

No. of digits between the 1st repeated pattern and decimal = 0

(Here, the first repeated pattern is "3" which comes right after the decimal point)

So, multiply the given decimal by 1. Then, we have

**X = 3.3333...............----------(1) **

No. of digits between the 2nd repeated pattern and decimal = 1

(Here, the second repeated pattern is "3" which comes one digit after the decimal point)

So, multiply the given decimal by 10. Then, we have

**10X = 33.3333...............----------(2)**

(2) - (1) --------> 9X = 30

X = 30 / 9 = 10 / 3

**Hence, 3.3333.............. = 10 / 9**

**Problem 6 :**

Covert the given non-terminating repeating decimal into fraction

**1.023562562562..........**

**Solution : **

Let X = 1.023562562562.............

Here, the repeated pattern is 562

No. of digits between the 1st repeated pattern and decimal = 3

So, multiply the given decimal by 1000. Then, we have

**1000X = 1023.562562562...............----------(1) **

No. of digits between the 2nd repeated pattern and decimal = 6

So, multiply the given decimal by 1000000. Then, we have

**1000000X = 1023562.562562562...............----------(2)**

(2) - (1) --------> 999000X = 1022538

X = 1022539 / 999000

**Hence, 1.023562562562.......... = ****1022539 / 999000**

After having gone through the stuff and examples, we hope that the students would have understood, "non-terminating repeating decimal"

**Related Topics**

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__Converting improper fractions into mixed fractions__

__Converting mixed fractions into improper fractions__

**Converting decimals into fractions**

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